Saturday, November 23, 2013

Find the value of x Right triangle with the sides x, 2x+4, 2x+6

sides: x, 2x+4=2(x+2), 2x+6=2(x+3) 
so we write: 

x%5E2%2B%282%28x%2B2%29%29%5E2=%282%28x%2B3%29%29%5E2 
x%5E2%2B4%28x%5E2%2B4x%2B4%29=4%28x%5E2%2B6x%2B9%29 
x%5E2%2B4%28x%5E2%2B4x%2B4%29-4%28x%5E2%2B6x%2B9%29=0 

x%5E2-8x-20=0 
x%5E2-10x%2B2x-20=0 
x%28x-10%29%2B2%28x-10%29=0 
%28x-10%29%28x%2B2%29=0 
which gives us x=-2 or x=10 
but x>0 

so only x=10 works :) 

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