Saturday, November 23, 2013

Find the equation of the tangent line for f(x)=3x^2-x at the given point (-2,14)

f' = 6x-1 
f'(-2)=6(-2)-1=-13 

so m=-13 
y-b=m(x-a)
y-14=-13(x--2) 
y-14=-13(x+2) 

:)

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