Saturday, November 16, 2013

Solve for x: log2(x-2)=log4(x)

4%5Elog%282%2Cx-2%29=4%5Elog%284%2Cx%29 


2%5E%282%2Alog%282%2C%28x-2%29%29%29=x 

%28x-2%29%5E2=x 


which has solutions x=1 and x=4. But x=1 is extraneous 
...so x=4

No comments: