there is a three digit number one digit is prime another is a square number the last one is not prime or square. the number is not divisible by three. what is the greatest possible value of the number

we try the first digit as 9 because it is a perfect square and the greatest 3-digit numbers have 9 in their thousands place
the last one is not prime, so the middle number must be the prime so we choose 7 (greatest prime less than 9) 
6 is not a prime, it is our only last digit possible if we require our number to not be a multiple of 3 
so our number is 976