Sunday, November 17, 2013

If f( x ) = ( x - 2 )^3 , then f^-1 ( x ) =

y=+%28+x+-+2+%29%5E3+
root%283%2Cy%29=x-2
x=root%283%2Cy%29%2B2 
therefore 
f%5E-1%28x%29=root%283%2Cx%29%2B2
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