Showing posts with label Geometry. Show all posts
Showing posts with label Geometry. Show all posts

Friday, June 5, 2015

Wednesday, June 3, 2015


Two chords intersect with the measures shown in the drawing.
What is the value of x?


Solution:

we know that the product of the lengths of one intersecting chord must be equal to the product of the lengths of the other, so...



For what value of x is if the lines are parallel in this figure?





Solution:
We know that x and 40.03 are supplementary, so x+40.03=180. Therefore x=139.97 degrees

Sunday, May 31, 2015

Find x.



What is the value of x?


Solution:


TV is a diameter, and SU is perpendicular to TV. This means that x=8

Friday, May 29, 2015

Given quadrilateral KLMN, what is the value of x?




Given quadrilateral KLMN, what is the value of x?


Solution:

3x+x+25+80+95=360 (why?)

4x+200=360

4x=160

x=40

Monday, April 21, 2014

The sides of an equilatersl triangle are 3x-1, 5y, and x+13. Find the measures of each side.

equilateral => 3x-1=x+13 => x=7
and x+7 turns into 7+13=20
and so all sides are 20 units

:)

In Triangle ABC, Angle B = 15 degrees less than twice angle A and Angle C is more than angle A. Find angle C.

B=2A-15
C>A
and A+B+C=180
which becomes...
A+(2A-15)+C=180
C=180+15-3A
C=165-3A

so
0%3CA%3C55
Which sets our boundary to test for valid triangles. After trial and error (there's probably a better way) we can deduce the following.
The least value for C under these conditions is C=42 and the greatest is a little more than 142
so...these are pretty good approximations
8%3CA%3C41
42%3CC%3C142 

What is the area of a circle whose circumference is π? Leave your answer in terms of π?

C=pi=2%2Api%2Ar

so
r=1%2F2

A=pi%2Ar%5E2=pi%2F4

Thursday, April 3, 2014


what is the hight of a triangle with two 13 yd sides? explain?

Your Answer:
first we assume that the base is an unknown value...

if the sides are both 13 yd - the triangle must be isosceles
and from geometry we know that the height is
h=%28sqrt%283%29%2F2%29%2Al
so in our case
h=%28sqrt%283%29%2F2%29%2A13

The length of a rectangle is 5 inches more than double its width. If the perimeter is 70 inches, find the dimensions of the rectangle by using a system of equations.

length of a rectangle is 5 inches more than double its width means:
l=2w+5
the perimeter is 70 inches means:
2l+2w=70
or l+w=35
subbing in for l and simplifying...
(2w+5)+w=35
3w=30
so w=10
then that means
l+10=35
and so l=25
the dimensions must be: 25 inches x 10 inches

The length and width of a rectangle are consecutive even integers. The perimeter is 44 meters. Find the length and width.

2(l+w)=P
2(l+l+2)=44
2l+2=22
2l=20
l=10
length:10, width:12