(1) n+d=120 <- number of coins
(2) 5n+10d=10(100) <- amount of money
5*(1) gives us...
5n+5d=600
(2) - 5 * (1) gives us...
10d-5d=400
5d=400
d=80
80 dimes and 40 nickels
(2) 5n+10d=10(100) <- amount of money
5*(1) gives us...
5n+5d=600
(2) - 5 * (1) gives us...
10d-5d=400
5d=400
d=80
80 dimes and 40 nickels
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