Wednesday, May 8, 2013

perimeter = 50, area = 144 what is the length and width of this rectangle?

p=2l%2B2w 
A=lw 
2l%2B2w=50 
or 
l%2Bw=25 
so 
l=25-w 
next we look at 
lw=144 
Which becomes: 

%2825-w%29w=144 
25w-w%5E2=144 

after rearranging... 
w%5E2-25w%2B144=0 
after solving 
w=9 or w=16 
let's use w=9 (it's smaller so maybe easier to work with) 

l=25-w=25-9=16 

so l=16, w=9

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