informally this problem only requires a working knowledge of counting money
12 dimes: $1.20
3 nickels:$0.15
buck thirty five!
formally:
coins: n+d=15
cash value: 0.05n+0.10d=$1.35 (which we multiply by 20 for convenience)
n+2d=27
then
(n+2d)-(n+d)=27-15
d=12
so n=3
:)
12 dimes: $1.20
3 nickels:$0.15
buck thirty five!
formally:
coins: n+d=15
cash value: 0.05n+0.10d=$1.35 (which we multiply by 20 for convenience)
n+2d=27
then
(n+2d)-(n+d)=27-15
d=12
so n=3
:)
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