Saturday, May 18, 2013

Internet Company A charges a $25 fee plus an additional $0.35 per hour. Internet Company B charges a $10 fee plus an additional $0.50 per hour. For what number of hours are the charges for both companies the same?

First we write their total charges as equations. Then we solve for t - the number of hours when both charges are equal 
A=0.35t%2B25 

B=0.50t%2B10 

When they charge the same A=B and we can write 

0.35t%2B25=0.50t%2B10 

25-10=0.5t-0.35t 

15=0.15t 



so t=100 hours 


:)

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