How many gallons of a 10% antifreeze solution: 0.10x
and a 25 % Antifreeze solution must be mixed: 0.25y
to make 3 gallons of a 20 % antifreeze solution: (3)(0.20)=0.6
but x+y=3 (so y=3-x)
and we write
0.1x+0.25(3-x)=0.6
which gives us x=1 gallon
:)
and a 25 % Antifreeze solution must be mixed: 0.25y
to make 3 gallons of a 20 % antifreeze solution: (3)(0.20)=0.6
but x+y=3 (so y=3-x)
and we write
0.1x+0.25(3-x)=0.6
which gives us x=1 gallon
:)
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