Monday, May 20, 2013

Solve sec^2(x)+tan(x)-1=0

Assuming you mean solve the equation 
%0D%0Asec%5E2%28x%29%2Btan%28x%29-1=0%0D%0A 

here goes... 

%0D%0Asec%5E2%28x%29-1%2Btan%28x%29=0%0D%0A 



%0D%0Atan%5E2%28x%29%2Btan%28x%29=0%0D%0A 



%0D%0Atan%28x%29%281%2Btan%28x%29%29=0%0D%0A 

which leads to 

%0D%0Atan%28x%29=0%0D%0A 

and so 
x=n%2Api 

or 

%0D%0Atan%28x%29=-1%0D%0A 

which leads to 

%0D%0Ax=%28-pi%29%2F4%2Bn%2Api%0D%0A 

:)
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