Find all real numbers that satisfy the equation. cos 2x = sqrt(3)/2

or


where n is an integer, then...

Solve for all solution: sin(3x)cos(6x)-cos(3x)sin(6x)=-0.9

Use angle subtraction identity to get:
 

then since sine is an odd function



which leads to

Solve: 2sec²θ+5tanθ=3

Find all solutions of the equation below on the interval [0,2pi). sin 3t + sin t = 0 t=?

leads to
 or 

which leads to

so that
{0, pi/2, pi, 3pi/2}

Solve: (sin(2x)+cos(2x))^2=1

After expanding and simplifying we can write 
 

as 

 

Therfore 
 

becomes 

 

and so 


 


which has solutions... 

 

where n is an integer. 

:)

Solution for cos4x=cos2x

cos4x=cos2x

tells us that 

 

which gives us 

 
or 
 

where n is an integer

cos2x-cos6x=0 find the exact values of all solutions between 0 and pie

 
 
so 
 
then for  
we get 
,, 

Solve sec^2(x)+tan(x)-1=0

Assuming you mean solve the equation 
 

here goes... 

 



 



 

which leads to 

 

and so 
 

or 

 

which leads to 

 

:)

Solve secΘ-2tanΘ=0

Solution:

 

 

 

but the denominator contributes no zeros... 

 

 

on 

 

or 
 

so the general solution is 

or