Sunday, May 12, 2013

for each of the following find: A) the vertex, B)the y intercept, C) the x intercept of f(x)=(x-1)^2-2

This parabola is in standard form - which is nice: 
%0D%0Af%28x%29=%28x-1%29%5E2-2%0D%0A 
%0D%0Af%28x%29=a%28x-h%29%5E2%2Bk%0D%0A 
%0D%0AV%28h%2Ck%29%0D%0A 


so our vertex is (1,-2) 

to get the y-intercept set x=0, then 


f%280%29=%280-1%29%5E2-2=1-2=-1 

to get the x-intercept set f(x)=0, then 

%0D%0A0=%28x-1%29%5E2-2%0D%0A 
%0D%0A2=%28x-1%29%5E2%0D%0A 


%0D%0Aabs%28x-1%29=2%0D%0A 

so that 
x-1=2 or x-1=-2
x=0 or x=-1 

x-intercepts: {0, -1} 

:)

No comments: