Tuesday, August 13, 2013

Solve 4(x+2)^2+320=0

%0D%0A+4%28x%2B2%29%5E2%2B320=0%0D%0A 

%0D%0A+%28x%2B2%29%5E2=-320%2F4%0D%0A 

Square rooting both sides then subtracting 2 (from both sides) leads to 

%0D%0Ax-2%2B2%2Ai%2Asqrt%285%29%0D%0A 

or 

%0D%0Ax=-2-2%2Ai%2Asqrt%285%29%0D%0A

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