f(x)= x^3- 8x^2+ 25x-26
working with the expression...
x^3- 8x^2+ 25x-26=
x^3- 8x^2+12x +13x-26=
x(x^2-8x+12)+13(x-2)=
x(x-2)(x-6)+13(x-2)
(x-2)(x^2-6x+13)
now a=1,b=-6, c=13
working with the expression...
x^3- 8x^2+ 25x-26=
x^3- 8x^2+12x +13x-26=
x(x^2-8x+12)+13(x-2)=
x(x-2)(x-6)+13(x-2)
(x-2)(x^2-6x+13)
now a=1,b=-6, c=13
Solved by pluggable solver: SOLVE quadratic equation with variable |
Quadratic equation (in our case ) has the following solutons: For these solutions to exist, the discriminant should not be a negative number. First, we need to compute the discriminant : . The discriminant -16 is less than zero. That means that there are no solutions among real numbers. If you are a student of advanced school algebra and are aware about imaginary numbers, read on. In the field of imaginary numbers, the square root of -16 is + or - . The solution is Here's your graph: |
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