Thursday, April 3, 2014

Find all solutions of the equation below on the interval [0,2pi). sin 3t + sin t = 0 t=?

sin%283t%29+=+sin%28-t%29
leads to
3t+=+2n%2Api-t+ or 3t=%282n%2B1%29%2Api-%28-t%29
which leads to
t=n%2F2%2A+pi
so that
{0, pi/2, pi, 3pi/2}

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