Friday, April 4, 2014

Solve: 5^(2x)-3*5^x+2=0

if
u=5%5Ex
then we have
u%5E2-3u%2B2=%28u-2%29%28u-1%29=0%0D%0A%0D%0Aso+that%0D%0A%0D%0A%7B%7B%7B5%5Ex=2 or 5%5Ex=1
and therefore
x=log%285%2C2%29 or x=0
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