Thursday, April 3, 2014

Use the given zero to find all the zeros of the function: f(x)=x^3+x^2+9x+9 zero: 3i i=imaginary number

since 3i is a root, then so is -3i and thus so is x^2+9. Then factoring we can say...
x%5E3%2Bx%5E2%2B9x%2B9=x%28x%5E2%2B9%29%2B1%28x%5E2%2B9%29=%28x%2B1%29%28x%5E2%2B9%29

so...

{-1, 3i, -3i}

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