Saturday, November 9, 2013

Find a complex number z satisfying the given equation z^2 = i

z%5E2+=+i
z%5E2+-+sqrt%28-1%29+=0 
z%5E2-root%284%2C-1%29%5E2=0 
%28z%2Broot%284%2C-1%29%29%28z-root%284%2C-1%29%29=0 
solutions: 
z=root%284%2C-1%29 
or 
z=-root%284%2C-1%29
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