Friday, May 3, 2013

Solve the following exponential equation 2^(x+1) = 5^(1-x)

+2%5E%28x%2B1%29+=+5%5E%281-x%29 
+2%5Ex%2A2+=+5%2A5%5E%28-x%29 
2%5Ex%2F5%5Ex=5%2F2 
%282%2F5%29%5Ex=5%2F2 
%282%2F5%29%5Ex=5%2F2 
%282%2F5%29%5Ex=%282%2F5%29%5E%28-1%29 
after taking log of both sides and cancelling (i.e. if the bases are equal the the exponents are also equal to each other) 


x=-1 
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