Friday, May 3, 2013

Solve the following exponential equation 3^(2x-1) = 2^(x+2)

3%5E%282x-1%29+=+2%5E%28x%2B2%29 
Expanding exponents... 
3%5E%282x%29%2A3%5E%28-1%29+=+2%5Ex%2A2%5E2 
simplifying... 
3%5E%282x%29%2F3+=+2%5Ex%2A4 
%283%5E2%29%5Ex%2F3=4%2A2%5Ex 
Next we isolate x... 
9%5Ex%2F3=4%2A2%5Ex 


9%5Ex%2F2%5Ex=4%2A3 


Key step: we can combine the bases under the exponent since the exponent for both of them is the same... 
%289%2F2%29%5Ex=12 
log%28%289%2F2%29%5Ex%29=log12 
x%2Alog%289%2F2%29=log12%29 
x=log12%2Flog%289%2F2%29 
which can be rewritten as... 
log12%2F%28log9-log2%29 

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