A rectangle is 3 meters longer than it is wide. If the width of the rectangle is doubled and the length is decreased by 4 meters, the area is unchanged. Find original length and width
Solution:
l=w+3 so
After w is doubled and length is decreased by 4,
Now since the area has not changed
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So width is 0 or 5m
We can discard the 0 solution.
Length is w+3, so length is 8m
Solution:
l=w+3 so
After w is doubled and length is decreased by 4,
Now since the area has not changed
So width is 0 or 5m
We can discard the 0 solution.
Length is w+3, so length is 8m
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