Tuesday, April 30, 2013

Find the remaining angles and sides of each triangle if it (they) exists. If no triangle exists, say “no triangle” A=10(degrees), B=40 (degrees), side c=2

A=10(degrees), B=40 (degrees), side c=2




Solution:

A=10deg, B=40deg, c=2 

First let's find the missing angle: 


C=180-%2810%2B40%29 


We can solve this triangle by using the Law of Sines. 


a%2FsinA=c%2FsinC
a%2Fsin10=2%2Fsin130
a=%282%2Asin10%29%2FSin130 


which is approximately 0.453 
Similarly...


b=%282%2Asin40%29%2FSin130 


which is approximately 1.678

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