log functions are inverses of exponential functions. We have two choices. In this case we'll use log base 8 (can you see why?).


First we rewrite so that out exponents are now products and we use the fact that

to simplify our equation and we get:




First we rewrite so that out exponents are now products and we use the fact that
to simplify our equation and we get:
No comments:
Post a Comment