Friday, January 2, 2015

Find the dimensions of a rectangle whose perimeter is 52 and the area is 96


P=2%28l%2Bw%29=52
lw=96

then
l=96%2Fw
l%2Bw=26
96%2Fw%2Bw=26

w%5E2-26w%2B96=0

with the solution:
w=13+-+sqrt%2873%29
l=13+%2B+sqrt%2873%29
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