Showing posts with label Triangles. Show all posts
Showing posts with label Triangles. Show all posts

Saturday, December 13, 2014

Triangle ABC is inscribed in a circle. AB is 12, AC is 6 and BC is 6 square root 3. Find arc BC.

These measures tell us that the triangle is a 30-60-90 triangle with a hypotenuse opposite the side AB and since we can see that arc BC is the arc of least measure, it must be 60 degrees

Friday, April 4, 2014

In a ΔABC, angle B = 90 degrees, AB = 6 units and AC = 10 units then the length of angle bisector AD from angle A is

 cosA=6/10=3/5 
A=arccos(3/5) - about 53.13 deg
so half is about A2=26.57 deg
therefore
cosA2=6/AD
cos26.57=6/AD
AD=6/cos26.57=6.71

Monday, July 15, 2013

find the area triangle of sides 5cm,6cm,7cm

%0D%0AA=sqrt%28s%28s-a%29%28s-b%29%28s-c%29%29%0D%0A


where the semiperimeter is

%0D%0As=%28a%2Bb%2Bc%29%2F2%0D%0A 

a=5, b=6, c=7, s=18/2=9 

by substitution and simplification we get 
A=6sqrt%286%29 


:)

Monday, June 17, 2013

Two sides of a triangle are twelve feet, what is the length of the third side?

Since we are only given two congruent sides, we cannot specify the length the third side. However we can describe what it must be... 

First off, our triangle must be isosceles and so the base angles must be congruent. Let's call the unknown side u and the angle between the congruent legs x, then the base angles must be: 

x%2B2base=180 

and so 

%0D%0Abase=%28180-x%29%2F2%0D%0A 
Next we can use the Law of Sines to find u 

u%2Fsin%28x%29=12%2Fsin%28%28180-x%29%2F2%29 

but 
%0D%0Asin%28%28180-x%29%2F2%29=cos%28x%2F2%29%0D%0A 

so we can write 



%0D%0Au=%2812sin%28x%29%29%2Fcos%28x%2F2%29%0D%0A 


:)

Saturday, June 1, 2013

How do I work out the height of a triangle when the angle of two sides are 45 degrees and 37 degrees?

Clearly we cannot specify the height without knowing any lengths of sides, but we can describe the relationship between the height, angle measures and side lengths: 

h%5B1%5D=asin%2845%29
h%5B2%5D=bsin%2837%29
h%5B3%5D=csin%2883%29 


:)

Friday, May 10, 2013

In Triangle ABC, if angle A=60 degrees and angle B is greater than angle C, then the longest side is ?

The sum of the measures of a triangle is 180 degrees. If the measure of angle B is greater than that of B and they must sum to 120 degrees, then the measure of B must exceed 60 and so it must be the greatest

Thursday, May 9, 2013

Find the area of triangle ABC to the nearest tenth if necessary. A= 35 degrees b=3 ft c= 7 ft

the area is found immediately by the formula:
A=%281%2F2%29%2Ab%2Ac%2Asin%28A%29=%281%2F2%29%2A3%2A7%2Asin%2835%29

which when calculated gives: A=6.0 square feet (when you check make sure your calculator is in degree mode)
:)

Tuesday, April 30, 2013

A triangle is such that its medium side is three times as long as its shortest side, and its longest side is five inches longer than four times its shortest side. The perimeter of the triangle is 69inches. Find the length of the medium side of the triangle

Solution:


First we decide on names for our sides: 

s-short side
m-medium
l-long 

Next let's look at each statement carefully... 

medium side is three times as long as its shortest side means: 

m=3s 

longest side is five inches longer than four times its shortest side means: 

l=4s%2B5 

perimeter of the triangle is 69 inches means: 

s%2Bm%2Bl=69 

Now we can substitute values: 

s%2Bm%2Bl=69 

becomes 

s%2B%283s%29%2B%284s%2B5%29=69 

Adding s-terms... 
8s%2B5=69 
8s=64 

so s=8 

Now 
m=3s=3%2A8=24