Monday, July 8, 2013

Solve 2x^2e^x=3xe^x

%0D%0A2x%5E2e%5Ex=3xe%5Ex%0D%0A 

%0D%0A2x%5E2e%5Ex-3xe%5Ex=0%0D%0A 

%0D%0Ax%282x-3%29e%5Ex=0%0D%0A 
Now the zero product property tells us 
x=0, x=3/2
:)
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