Apply the distributive law to write an equivalent form of the follows: 1.x+nx+2x 2.(x+3)(5)+(x+3)(n) 3.(x+5)(n)+(x+5)

 1.x+nx+2x = 3+n)x



 2.(x+3)(5)+(x+3)(n) = (x+3)(n+5)


 3.(x+5)(n)+(x+5) = (x+5)(n+1)


:)