assume that SAT scores are normally distributed with mean u=1518 and standard deviation of 325 B) If 100 SAT scores are selected find the probability that they have a mean less than 1500

n=100
u=ux=1518
o=325
ox=325/root(100)=32.5 


P(x<1500)=
P((x-ux)/ox < (1500-1518)/32.5)=
P(z<-0.5538)=
0.2898