A farmer looks out into the barn yard and sees the pigs and chickens. He says to his daughter, I count 40 heads and 100 feet . How many pig s and how many chicken are there?
Solution:
Let's use
P-#pigs
C-#chickens
I count 40 heads: every animal has a head so...
...and 100 feet...
Pigs have 4 feet so 4P is the number of Pig's feet he sees and by the same thinking 2C is how many Chicken's feet. So...
To make our work easier we'll divide every term by 2...
We have 2-equations and 2-unknowns:
From the top equation we can say
Next
becomes...
From which we can quickly deduce that there are 10 pigs. And since there are 40 animals there must be 30 chickens.
:)
P-#pigs
C-#chickens
I count 40 heads: every animal has a head so...
...and 100 feet...
Pigs have 4 feet so 4P is the number of Pig's feet he sees and by the same thinking 2C is how many Chicken's feet. So...
To make our work easier we'll divide every term by 2...
We have 2-equations and 2-unknowns:
From the top equation we can say
Next
becomes...
From which we can quickly deduce that there are 10 pigs. And since there are 40 animals there must be 30 chickens.
:)
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