If the question is: find 19 consecutive numbers whose sum is 95 then this is our solution:
Starting with n we write: n+(n+1)+(n+2)+...=95
As we can see this equation has 19 terms - quite long so let's use summation notation:
The equation simplifies to:
which simplifies further to
so n=-4 and our numbers are:
-4, -3, -2, -1, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, and 14
:)
Starting with n we write: n+(n+1)+(n+2)+...=95
As we can see this equation has 19 terms - quite long so let's use summation notation:
The equation simplifies to:
which simplifies further to
so n=-4 and our numbers are:
-4, -3, -2, -1, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, and 14
:)
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