y=ax^2+bx+c
(0,10) => c=10
(1,15) => a+b+10=15 or a+b=5
(-1,7) => a-b+10=7 or a-b=-3
adding the two last equations yields 2a=2 so that a=1
and from the second equation a+b=5 we conclude b=4
:)
(0,10) => c=10
(1,15) => a+b+10=15 or a+b=5
(-1,7) => a-b+10=7 or a-b=-3
adding the two last equations yields 2a=2 so that a=1
and from the second equation a+b=5 we conclude b=4
:)
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