One number is 3 times another. If the sum of their reciprocals is 2/9, find the two numbers.

y = 3x 
1/x + 1/y = 2/9 
or 
1/x + 1/(3x) = 2/9 
3/(3x)+1/(3x) = 2/9 
4/(3x) = 2/9 
taking reciprocals: 
(3x)/4 = 9/2 
(4/3)((3x)/4) = (4/3)(9/2) 
x=6 

:)