Wednesday, July 31, 2013

cos2x-cos6x=0 find the exact values of all solutions between 0 and pie

cos2x-cos6x=0 
cos2x+=+cos6x 
so 
6x+=+2pi%2An%2B-+2x 
then for 0%3Cx%3Cpi 
we get 
pi%2F4,pi%2F2, %283pi%29%2F4
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