Monday, July 15, 2013

find the area triangle of sides 5cm,6cm,7cm

%0D%0AA=sqrt%28s%28s-a%29%28s-b%29%28s-c%29%29%0D%0A


where the semiperimeter is

%0D%0As=%28a%2Bb%2Bc%29%2F2%0D%0A 

a=5, b=6, c=7, s=18/2=9 

by substitution and simplification we get 
A=6sqrt%286%29 


:)

No comments: