Wednesday, July 24, 2013

One-fourth of the sum of three consecutive integers is 12 less than the smaller integer

n - least number 
%0D%0A%281%2F4%29%28n%2B%28n%2B1%29%2B%28n%2B2%29%29=n-12%0D%0A 
then we can write 
%0D%0A4%281%2F4%29%283n%2B3%29=4%28n-12%29%0D%0A 

%0D%0A3n%2B3=4n-48%0D%0A 

so that n=51

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