Friday, June 14, 2013

Solve: sqrt(2t+4)= sqrt (t-1)


%0D%0Asqrt%282t%2B4%29=+sqrt+%28t-1%29%0D%0A 

%0D%0Asqrt%282t%2B4%29%5E2=+sqrt+%28t-1%29%5E2%0D%0A 

%0D%0Aabs%282t%2B4%29=+abs%28t-1%29%0D%0A 
leads to 

2t+4=t-1 
t=-5
(extraneous unless we allow for imaginary numbers) 
or 

2t+4=-(t-1) 
3t=3 
t=1
(extranoous) 

We see that over the reals this equation has no solution. Iver the complex numbers, x=-5 

:)

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