Find three consecutive odd intergers such that the sum of the first and second is equal to 23 less than the third

Find three consecutive odd integers: n+(n+2)+(n+4) 
such that the sum of the first and second is equal to 23 less than the third: 
n+(n+2)=(n+4)-23 

2n+2=n-19 
n=-21 



numbers: 

-21, -19, -17 

:)