use inverse tangent function:

Showing posts with label Angles. Show all posts
Showing posts with label Angles. Show all posts
Saturday, December 13, 2014
Sunday, December 29, 2013
find the complement and supplement of an angle with the given measure. a.)10° 10' 30" , b.)1° 40' 19"
a)
90°=89° 59' 60"
so...
complement:
89° 59' 60"-10° 10' 30"=
79° 49' 30"
supplement:
169° 49' 30"
b)
complement
89° 59' 60"-1° 40' 19"=
88° 19' 41"
supplement:
178° 19' 41"
90°=89° 59' 60"
so...
complement:
89° 59' 60"-10° 10' 30"=
79° 49' 30"
supplement:
169° 49' 30"
b)
complement
89° 59' 60"-1° 40' 19"=
88° 19' 41"
supplement:
178° 19' 41"
Tuesday, June 4, 2013
An angle is one third of it's complement. What is the measure of the angle?
angle:x
complement:y
so that x+y=90
An angle is one third of it's complement means x=y/3
so y=3x
x+3x=90
4x=90
x=22.5
:)
complement:y
so that x+y=90
An angle is one third of it's complement means x=y/3
so y=3x
x+3x=90
4x=90
x=22.5
:)
Wednesday, May 1, 2013
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