find the complement and supplement of an angle with the given measure. a.)10° 10' 30" , b.)1° 40' 19"

a)
90°=89° 59' 60"
so...
complement:
89° 59' 60"-10° 10' 30"=
79° 49' 30"
supplement:
169° 49' 30"
b)
complement
89° 59' 60"-1° 40' 19"=
88° 19' 41"
supplement:
178° 19' 41"

two complementary angles are in the ratio 3:2

1) x/y = 3/2 
or (2/3)x=y 

2) x+y=90 

together 
x + (2/3)x=90 
5/3 x = 90 

(3/5)(5/3)x=(3/5)*90 
x=54 
thus y=36 

:)