for the point (4,3) we can write 
for the point (5,6) we can write
then taking the quotient of these two equations leads to

s we see that

Now we can use either point (we'll go with (4,3)) and b directly to write


so,

for the point (5,6) we can write
then taking the quotient of these two equations leads to
s we see that
Now we can use either point (we'll go with (4,3)) and b directly to write
so,
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