Expanding the numerator
Wednesday, December 31, 2014
In OPQ, o = 870 inches, P = 80 degrees, and Q = 9 degrees. Find the length of p to the nearest 10th of an inch.
We'll denote the measure of angle X as
In any triangle the sum of the angles is 180 degrees, so
so we know
Now using the Law of Sines we write:
which leads to
In any triangle the sum of the angles is 180 degrees, so
so we know
Now using the Law of Sines we write:
which leads to
The function f(x)=2x/3x-5 is one-to-one. find its inverse and check your answer
To find the inverse we can solve for x to convert it to the dependent variable:
Once their roles have reversed, the resulting expression is the inverse:
To check we take the two appropriate inverses to see if they each recover the input (i.e. x).
Checking...
Tuesday, December 30, 2014
If $1000 is invested in an account paying 12% annually compounded continously, how long will it take to double the investment?
For continuous compounding we use:
so we can write:
taking the natural log of both sides leads to
so time is about 5.78 years
solve the equation ln(x)- ln (x-3) = ln(5)
combining logs...
raising e to both sides of the equation...
which leads to...
and so...
raising e to both sides of the equation...
which leads to...
and so...
Solve: log(x+4) + log(x)=9
Combining into one log...
raise 10 to both sides of the equation...
After solving we note that only positive numbers are solutions (Why?)
Simplify: (sin(f+g)+sin(f-g))/(cos(f+g)+cos(f-g))
After expanding all 4 expressions using sum/difference identities we get:
which simplifies to...
which simplifies to...
and then to...
Saturday, December 13, 2014
Find the intercepts and asymptotes. (If an answer does not exist, enter DNE.) r(x)=27/(x-3)^2
x-intercepts: Zeros only occur in the numerator so DNE
y-intercepts:
27/(-3)=-9
(0, -3)
VA:
x-3=0
x=3
HA:
as |x| --> oo
r --> 0
y=0
y-intercepts:
27/(-3)=-9
(0, -3)
VA:
x-3=0
x=3
HA:
as |x| --> oo
r --> 0
y=0
Triangle ABC is inscribed in a circle. AB is 12, AC is 6 and BC is 6 square root 3. Find arc BC.
These measures tell us that the triangle is a 30-60-90 triangle with a hypotenuse opposite the side AB and since we can see that arc BC is the arc of least measure, it must be 60 degrees
the cost of a telephone call is 5 pesos for the first three minutes and an additional of 2 pesos for each additional minute or fractional part thereof. find the cost of all call lasting: a) .5 min, b) 3 minutes, and c) 5 minutes
c(t)=5+2(t-3), t>3
a) c(0.5)=5
b) c(3)=5
c) c(5)=5+2(5-3)=5+2(2)=9
How do you use the intermediate value theorem to show the polynomial function that has a zero in the given. [1.3, 1.9], f(x)= x^5-x^4+3x^3-4x^2-16x +15
f(1.3)=-5.112 (approx.)
f(1.9)=2.465 (approx.)
the theorem tells us that since there is a sign change for f on the interval there must be a zero on the interval
f(1.9)=2.465 (approx.)
the theorem tells us that since there is a sign change for f on the interval there must be a zero on the interval
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