Monday, June 24, 2013

The length of a rectangle is 10 ft longer than twice the width.If the perimeter is 116 ft find the lenght and width of the rectangle.

l=2w+10 
P=2(l+w)=116 

so 
l+w=58 
2w+10+w=58 

3w=48 
w=16 

l=2(16)+10=42 

length: 42 ft
width: 16 ft

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