Sunday, June 2, 2013

Sqrt(4-3x)=x How do I find the real solutions? Thanks :)

%0D%0Asqrt%284-3x%29=x%0D%0A 

%0D%0Asqrt%284-3x%29%5E2=x%5E2%0D%0A 

%0D%0Ax%5E2%2B3x-4=0%0D%0A 

x=1, x=-4 
but square roots are never negative so x=1 

:)

No comments: