a line perpendicular to a vertical line has a slope of m=0, So we know y=-7
Showing posts with label Perpendicular Slope. Show all posts
Showing posts with label Perpendicular Slope. Show all posts
Thursday, April 3, 2014
Saturday, January 4, 2014
Saturday, November 23, 2013
Find the slope of a line perpendicular to each given line. y=-5/3x+3
the perpendicular slope is the negative reciprocal of the original so it is 3/5
:)
:)
Saturday, November 9, 2013
What is an equation that is perpendicular to y+4=7(x-7)?
y+4=-1/7(x-7) qualifies because (7)(-1/7)=-1
Tuesday, August 13, 2013
Determine whether the lines are parallel, perpendicular, or neither. 2x-y=-10, 2x+4y=2
m=-A/B
m1=-2/(-1)=2
m2=-2/4=-1/2
They are perpendicular!
:)
m1=-2/(-1)=2
m2=-2/4=-1/2
They are perpendicular!
:)
Saturday, August 3, 2013
Side AB of rectangle ABCD is contained within the line y = 7x - 9. What is the slope of the adjacent side, BC?
For a rectangle, adjacent sides are perpendicular, therefore

Sunday, June 23, 2013
If a line has a gradient of 5/2 what will the gradient be of a perpendicular line be if a line has a gradient of 5/2? What will the gradient be of a parallel line be?
The slopes of perpendicular lines have a product of -1. So can write:
Parallel lines have the same slope:

Parallel lines have the same slope:
Friday, June 21, 2013
Determine whether the pair of lines is parallel, perpendicular, or neither 3x+y=7, -2×+6y=6
3x+y=7,
-2×+6y=6
or
3x+y=7, m=-3
×-3y=-3, m=1/3
These have have a product of -1 so they are perpendicular
-2×+6y=6
or
3x+y=7, m=-3
×-3y=-3, m=1/3
These have have a product of -1 so they are perpendicular
Wednesday, May 22, 2013
Determine whether the lines x-5y=15 and -5x-y+2=0 are parallel, perpendicular, or neither.
x-5y=15 has
and -5x-y+2=0 has
and so
they are perpendicular
:)
and -5x-y+2=0 has
and so
they are perpendicular
:)
Friday, May 10, 2013
Thursday, May 9, 2013
perpendicular to 3x+4y=12 passes through (3,2)
Your Answer:
has the slope
which is perpendicular to
our given point is (3,2), so using the point-slope form of the equation of a line we get:
:)
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