Saturday, January 3, 2015

Please solve |x^2+3x|=|x^2-2x|


removing the absolute vale leads to
case 1:
x%5E2%2B3x=x%5E2-2x or
case 2:
x%5E2%2B3x=-%28x%5E2-2x%29

case 1:

3x=-2x
5x=0
x=0

case 2:
x%5E2%2B3x=-x%5E2%2B2x
2x%5E2%2Bx=0
x=0 or x=-1%2F2

solutions: {0, -1/2}

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