Saturday, December 14, 2013

Two picture frames have the same area of 96 inches squared but different perimeters. What could the perimeters of the two frames be?

Both pictures must satisfy the equation:
A=96=l%5B1%5D%2Aw%5B1%5D=l%5B2%5D%2Aw%5B2%5D
So choosing valid values for any suitable pair of the four dimensions will produce different perimeters. For example:
l%5B1%5D=1l%5B2%5D=2
results in
P%5B1%5D=194
P%5B2%5D=100
and so on...

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