Wednesday, December 25, 2013

Alan participated in a car race in which he had to cover a distance of at least 50 kilometers. He had fuel in his car for a maximum distance of 53 kilometers. If the distance is given by S(t)=3t+47 , where (t) is the time in hours, find the minimum and maximum number of hours for which Alan can drive his car.

S%28t%29=3t%2B47=53
so
3t%2B47-47=53-47=6
t=2
In general his limits are:
0+%3C=+t+%3C=+2
but assuming he wants to stay in the race:
3t%2B47-47=50-47=3
t=1
and his limits are:
1%3C=t+%3C=2

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