Examples of Math Problems

examples of math problems that I like, solved, etc.

Saturday, September 7, 2013

length of a dog run is 9 feet more than twice the width and the perimeter is 34 feet, what is the length and width

1) l=2w+9
2) 34=2(l+w) 


from 2)...
 17=l+w
17=(2w+9)+w
17-9=3w
w=8/3 

so 
l=
2*8/3+9=
16/3+27/3=
43/3
Posted by Unknown at 2:10 PM No comments:
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Labels: Geometry, Perimeter, Word Problems

Four times a number added to 5 is divided by 6. The result is 7/2. Find the number.

(4x+5)/6=7/2
6(4x+5)/6=6*7/2
4x+5=21
4x=16
x=4
Posted by Unknown at 2:02 PM No comments:
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Labels: My Algebra.com posts, Word Problems

There is a certain number less than 100. The sum of the digits is 7 and the product of the digits is 6. What is the number?

we describe the number as 100=xy so that x is in the 10's place and y in the 1's place, then: 
1) x+y=7
2) xy=6 

x=6/y 
6/y+y=7
6+y^2=7y
y^2-7y+6=0
(y-6)(y-1)=0 
y=6 or y=1 

so we see that there are two numbers possible: 16 and 61
Posted by Unknown at 1:53 PM No comments:
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Labels: My Algebra.com posts, Word Problems

Friday, September 6, 2013

The graph is a parabola with vertex (3,-8) and passing through the origin. Write the quadratic equation of this graph.

We use the Standard Form: 
%0D%0Ay=a%2A%28x-h%29%5E2%2Bk%0D%0A
from the vertex we get:
%0D%0Ay=a%2A%28x-3%29%5E2-8%0D%0A 
since the origin is on the graph, 
%0D%0A0=a%2A%280-3%29%5E2-8%0D%0A 

9a=8 
a=9%2F8 

so we can write
%0D%0Ay=%289%2F8%29%2A%28x-3%29%5E2-8%0D%0A
Posted by Unknown at 6:43 PM No comments:
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Labels: My Algebra.com posts, Parabolas

the perimeter of a rectangle is 112 cm . the length is 30 cm . calculate the width .

P=2(l+w) 
w=P/2-l
w=112/2-30
w=26 cm
Posted by Unknown at 6:36 PM No comments:
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Labels: Geometry, My Algebra.com posts, Perimeter, Word Problems

The sum of two numbers is 78. The second number is 14 more than 3 times the first number. Find the two numbers.

x+y=78
y=3x+14 


so...
x+3x+14=78
4x+14=78
4x=64
x=16 

therefore...
y=78-16
y=62
Posted by Unknown at 6:29 PM No comments:
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Labels: My Algebra.com posts, Word Problems

a number added to eighteen times its reciprocal is eleven

x+18/x=11
x^2+18=11x
x^2-11x+18=0
(x-9)(x-2)=0 
x=2 or x=9
Posted by Unknown at 1:30 PM No comments:
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Labels: My Algebra.com posts, Quadratic Equations, Word Problems
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